[haskeline] #81: haskeline assumes all characters have width = 1
haskeline
haskeline at projects.haskell.org
Sat May 16 11:59:21 EDT 2009
#81: haskeline assumes all characters have width = 1
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Reporter: guest | Owner:
Type: defect | Status: new
Priority: major | Milestone:
Version: 0.6 | Resolution:
Keywords: |
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Comment (by judah):
Can you give some examples of double-wide or combining characters? Any
suggestions on how Haskeline could determine the width of a character?
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Ticket URL: <http://trac.haskell.org/haskeline/ticket/81#comment:1>
haskeline <http://example.org/>
My example project
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